A Body Cools In 7 Minutes From 60 To 40. This answer is FREE! See the answer to your question: A body

This answer is FREE! See the answer to your question: A body cools in 7 minutes from 60°C to 40°C. In the First case, T1 = 60°C, T2 = 40°C, To = 10°C, t = 7 A body cools in 7 minutes from 60^(@)C to 40^(@)C. While solving this problem, you will need some good knowledge in calculus. What will be its temperature after the next 7 minutes? The temperature of the surroundings is 10^(@)C. This is derived from the cooling constant So, the correct answer is “Option D”. What will be its temperature after the next 7 minutes The temperature of the surroundings is 10°C. What will be its temperature after the next - brainly. Using Newton's Law of Cooling, the body cools from 60°C to 40°C in 7 minutes. 7°C. A body cools in 7 minutes from `60^ (@)C` to `40^ (@)C`. Using Newton's Law of Cooling: This law A body cools from 80 C to 50 C after a time interval Δ t. (i) Now if after cooling from 40 ° C to 7 min the temperature of the body A body cools in 7 minutes from 60°C to 40°C. Assuming that the surrounding temperature is 20 C the temperature of the body after time interval of 2 Δ t is A body cools in 7 minutes from 60°C to 40° C. `32^ (@)C` B. The temperature of the surrounding is 10°C. What will be its temperature after the next 7 minutes? The temperature of the surrounding is `10^ (@)C`. Assume that Newton's law of cooling Tardigrade Question Physics A body cools in 7 minutes from 60 ° C to 40 ° C . What A body cools in 10 minutes from 60^@C to 40^@C . If the temperature of the surroundings is 20∘C Then temperature of the body after another 10 minutes will be Answer Step by step video, text & image solution for A body cools in 7 minutes from 60^ (@)C to 40^ (@)C What time (in minutes) does it take to cool from 40^ (@)C to 28^ (@)C if the surrounding A body cools in 7 minutes from 60∘C to 40∘C. By calculating the cooling constant and applying it again, we find that after another 7 minutes the Given that the initial temperature is 60°C, the final temperature is 40°C, and the time taken is 7 minutes, we can substitute these values into the formula: Rate of cooling = (60°C - 40°C) / 7 minutes According to Newton's law of cooling, [θ 1 − θ 2 t] = K [(θ 1 + θ 2 2) − θ 0] So that [60 − 40 7] = K [(60 + 40 2) − 10] ⇒ K = 1 14. `28^ A body cools in 7 minutes from 60∘C to 40∘C. What will be its temperature after next 7 minutes, if the temperature of the surroundings is 10∘C? A body cools in 7 min from 60^∘C to 40^∘C, then what will be its temperature after the next 7 min ? The temperature of the surroundings is 10^∘C. What will be its temperature after next 7 minutes? (Surrounding temperature is 10°C) (A) 28 °C (B) 30 °C (C) 32 °C (D) 34 °C Understanding the Situation: The body cools from 60°C to 40°C in 7 minutes, with the surrounding temperature remaining constant at 10°C. What will be its temperature after the next 7 minutes? The temperature of the surroundings is `10^ (@)C`. The drop in temperature is 20 °C, while the ambient temperature remains constant at 10 °C. Assume that Newton's law of cooling holds good throughout the process. What will be its temperature after the next 7 minutes? The temperature of the surrounding is 10∘C. A. What will be its temperature after next 10 minutes? The temperature of the surroundings is 10^@C . The temperature of the body after the next 7 minutes will be (1) 32°C (2) 30°C (3) 28°C (4) 34°C Similar Questions A body cools in 7 minutes from 60∘C to 40∘C. (a) 40^∘C ( A body cools in 7 min from 60°C to 40°C. The temperature of surrounding is 10°C. We use Newton’s law of cooling because this problem is based on heat loss which is 00:01 Hello friends today we are going to solve this problem in this problem a body cools in seven minutes from 60 degrees celsius to 40 degrees celsius what will be its temperature after the A body cools in 7 minutes from 60 C to 40 C What time (in minutes) does it take to cool from 40 C to 28 C if the surrounding temperature is 10 C ? Assume Newton’s Law of cooling holds This answer is FREE! See the answer to your question: A body cools in 7 minutes from 60° C to 40° C. com This answer is FREE! See the answer to your question: A body cools in 7 minutes from 60°C to 40°C. com. Using this information, we can find the 20. 81M subscribers Subscribe Manipal 2018: A body cools in 7 min from 60° C to 40° C. A body cools in 7 minutes from 60°C to 40°C what will be its temperature after next 5 minutes. What will be its temperature after the nex - brainly. What will be its temperature after the next 7 minutes ? The temperature of the surrounding is 10 ° C . Then what its temperature in next 7 minute (If the surrouding temperature is 10∘C ) After 7 minutes of cooling from 60°C to 40°C, the body continues to cool at a decreasing rate toward the surrounding temperature of 10°C. Assume that Newton's law of cooling holds good throught the A body cools in 7 minutes from 60∘ to 40∘C. com A body cools in 7 minutes from `60^ (@)C` to `40^ (@)C`. The body cools from 60°C to 40°C in 7 minutes. What will be its temperature after next 7 minutes, if the temperature of the surroundings is 10∘C? A body cools in 7 min from `60^C` to `40^C` What will be its temperature after the next 7 min? T Doubtnut 3. To solve the problem, we will use Newton's Law of Cooling, which states that the rate of change of temperature of an object is proportional to the difference between its temperature and the By applying Newton's Law of Cooling, we calculated that the temperature of the body after another 7 minutes would be approximately 30. What times (in min) does it take to cool from 40° C to 28° C, if surrounding temperature A body cools form 500C to 400C in 6 minute . Home A body cools in 7 minutes from `60^ (@)C` to `40^ (@)C`. Applying Newton's Law of Cooling suggests that A body cools in 7 minutes from 60°C to 40°C. When its surrounding temperature is 300C, what will be its temperature 12 min after the start of the experiment? surrounding temperature remains the same? According to Newton's Law of Cooling, the temperature of a body decreases exponentially with time. What time (in minutes) does it take to cool from 40° C to 28° C if the surrounding temperature is 10°C? Assume Newton's law of cooling hold? see full answer We know the initial temperature of the body (T_1 = 60°C), the final temperature after 7 minutes (T_2 = 40°C), and the temperature of the surroundings (T_surr = 10°C). We will again apply Newton's Law of Cooling: \ ( \frac {T2 - T} {t} = k \left ( \frac {T2 + T} {2} - Ts \right) \) Substituting the known values: \ ( \frac {40 - T} {7} = \frac A body cools in 7 minutes from `60^ (@)C` to `40^ (@)C` What time (in minutes) does it take to cool from `40^ (@)C` to `28^ (@)C` if the Initial Cooling: In the first interval, the body cools from 60 °C to 40 °C over 7 minutes. The temperature of a body falls from 50∘C to 40∘C in 10 minutes.

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